A load weighing 100 N is lifted with a racheg, while the work is done by 20 J. The point of application of the force that sets

A load weighing 100 N is lifted with a racheg, while the work is done by 20 J. The point of application of the force that sets the lever in motion has dropped by 10 cm. Determine to what height the load will rise ….

P1 = 100 N.

A = 20 J.

h2 = 10 cm = 0.1 m.

h1 -?

When lifting a load using a lever, the work of forces from opposite sides of the lever is the same: A1 = A2 = A.

Let us express the work A2 of the force applied to the lever: A2 = F2 * h2, where F2 is the value of the applied force.

F2 = A2 / h2 = A / h2.

F2 = 20 J / 0.1 m = 200 N.

Let us express the work of the load A1, which was lifted: A1 = P1 * h1.

F2 * h2 = P1 * h1.

The lifting height of the load will be determined by the formula: h1 = F2 * h2 / P1.

h1 = 200 N * 0.1 m / 100 N = 0.2 m.

Answer: using a lever, the load was raised to a height of h1 = 0.2 m.



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