A load weighing 150 kg lies at the bottom of the descending elevator car and presses on the floor with a force of 1300 N. Determine the acceleration of the elevator.
Let us find the normal weight of the load arising from the action of gravity:
P1 = mg = 1500N
Since the weight in the condition is less than the normal weight P1, the lift moves down. Moreover, m * a = 200H, a-in scalar form.
a = 200/150 = 4/3m / s ^ 2
Answer: a = 1.33 m / s ^ 2
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