A load weighing 2.5 kg falls from a height of 10 m. How much will its potential energy change in 1 s after the beginning

A load weighing 2.5 kg falls from a height of 10 m. How much will its potential energy change in 1 s after the beginning of the fall (the initial velocity of the load is zero).

Condition:
m = 2.5 kg.
g = 10m / s ^ 2.
t = 1 s.
h1 = 10 m.
To find :
E p. -? J.
Decision :

Method 1: (when g = 10 m / s ^ 2).
E p. = M * g * h.
h2 = g * t ^ 2/2.
h2 = 10 * 1/2 = 5 (m).
E p. = M * g * (h1-h2).
E p. = 2.5 * 10 * (10-5) = 2.5 * 10 * 5 = 125 (J).
Answer: 125 J.

Method 2: (when g = 9.8 m / s ^ 2).
E p. = M * g * h.
h2 = g * t ^ 2/2.
h2 = 9.8 * 1/2 = 4.9 (m).
E p. = M * g * (h1-h2).
E p. = 2.5 * 9.8 * (10-4.9) = 2.5 * 9.8 * 5.1 = 124.95 (J).
Answer: 124.95 J.