A load weighing 2 kg is lifted vertically upward, acting on it with a force of 60N. What is the change in the kinetic

A load weighing 2 kg is lifted vertically upward, acting on it with a force of 60N. What is the change in the kinetic and potential energy of the load when it is lifted to a height of 8M.

Given:

m = 2 kilograms is the mass of the load lifted vertically upwards;

F = 60 Newton – the force with which they act on the load;

H = 8 meters – the height to which the load is lifted;

g = 10 m / s ^ 2 – acceleration of gravity.

It is required to determine the change in the potential dEп (Joule) and kinetic dEк energies of the load at a height of 8 meters.

Before the load began to be lifted, its potential and kinetic energies were equal to 0. Then:

The change in potential energy is equal to:

dEп = Eph – Ep0 = m * g * h – m * g * 0 = m * g * h = 2 * 10 * 8 = 160 Joules.

The total work performed by the force F to lift the load to a height is equal to:

A = F * h = 60 * 8 = 480 Newtons.

Then, according to the law of conservation of energy, the change in the kinetic energy of the body will be equal to:

dEк = A – dEп = 480 – 160 = 320 Joules.