A load weighing 20 kg under the action of a force of 40 N moves uniformly along an inclined plane.

A load weighing 20 kg under the action of a force of 40 N moves uniformly along an inclined plane. Determine the efficiency of the inclined plane if its length is 2 m and its height is 10 cm.

Let’s translate into meters:
l = 2 cm = 0.02 m,
h = 10 cm = 0.1m,
Let’s find the efficiency:
Efficiency = A (useful) / A (full) * 100% = mgh / Fl * 100% = 20 * 10 * 0.1 / 40 * 0.02 * 100% = 20 / 0.8 * 100% = 25%
Answer: 25%



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