A load weighing 200 kg is lifted from the ground onto the roof of the house

A load weighing 200 kg is lifted from the ground onto the roof of the house. At the same time, its potential energy increased by 19.6 J. Find the height of the house.

Given:

m = 200 kg is the weight of the cargo;

Ep = 19.6 kJ = 19 600 J – change in the potential energy of the load during lifting (the value of 19.6 J indicated in the condition is not correct, most likely a mechanical error was made);

g = 9.8 N / m ^ 2 – free fall acceleration.

It is required to find h – the height to which the load was lifted.

We take the surface of the earth as the reporting point. That is, when the load was on the ground, its potential energy was equal to zero. When the load was lifted onto the roof of the house, its potential energy became equal to Ep. Potential energy is defined as:

Ep = m * g * h, hence:

h = Ep / m * g = 19600/200 * 9.8 = 10 m.

Answer: the height of the house is 10 meters.