A load weighing 3 kg was suspended to a spring with a stiffness of 3 kN / m. Determine the spring extension.

univerkov | November 27, 2020 | education

Given:
k = 3 kN / m = 3000 N / m.
m = 3 kg.
Find: Δx -?
Decision :
F control = k * Δx.
Ft-F control = 0.
Ft = F control.
m * g = k * Δx.
Δx = m * g / k.
[Δx] = (kg * m / s ^ 2) / (N / m) = N / N / m = m.
Δx = 30 * 10/3000 = 0.01 (m).
Answer: 0.01 or 1 cm.

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