A load weighing 4 kg is evenly lifted along an inclined plane 100 cm long and 10 cm high, applying

A load weighing 4 kg is evenly lifted along an inclined plane 100 cm long and 10 cm high, applying a force of 5 N to it. Find the efficiency of the inclined plane.

m = 4 kg.

g = 10 m / s2.

S = 100 cm = 1 m.

h = 10 cm = 0.1 m.

F = 5 N.

Efficiency -?

The efficiency factor The efficiency of the inclined plane shows what part of the expended work Az goes into the useful Ap: Efficiency = Ap * 100% / Az.

The useful work An when lifting a load along an inclined plane is expressed by the formula: An = m * g * h, where m is the body mass, g is the acceleration of gravity, h is the height of the inclined plane.

The expended work Az is expressed by the formula: Az = F * S.

Efficiency = m * g * h * 100% / F * S.

Efficiency = 4 kg * 10 m / s2 * 0.1 m * 100% / 5 N * 1 m = 80%.

Answer: the inclined plane has an efficiency of 80%.