A load weighing 40 kg is attached to the movable block. How much force must be applied to the cable to keep

A load weighing 40 kg is attached to the movable block. How much force must be applied to the cable to keep this weight in balance.

Since the movable block gives a 2-fold gain in strength, Pd = 2F, where Pd is the force acting on the load (Pd = Ft), F is the force applied to hold the load (N).
Pd = Ft = m * g, where m is the body mass (m = 40 kg), g is the acceleration of gravity (we take g = 10 m / s ^ 2).
Let’s calculate the force to keep the load in balance:
F = Pd / 2 = m * g / 2 = 40 * 10/2 = 200 N.
Answer: It is necessary to apply a force of 200 N.