A load weighing 50 kg rises vertically upward with a rope for 2 s to a height of 5 m.
| December 20, 2020 | education
A load weighing 50 kg rises vertically upward with a rope for 2 s to a height of 5 m. The initial speed of the load is zero. The force arising in the rope is equal.
F = ma
s = v0 * t + at ^ 2/2.
s = at ^ 2/2.
a = 2s / t ^ 2.
F = m * ((2s) / (t ^ 2)).
F = 50 * ((2 * 5) / (2 * 2)) = 125 N.
Answer: 125H
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