A load weighing 500 kg falls freely within 10 s. What kind of work does gravity do?

Initial data: m (weight of the load) = 500 kg, t (duration of the fall of the load) = 10 s, the fall of the load is considered free (V0 = 0 m / s).
Constants: g = 10 m / s ^ 2 = a.
The work force of gravity can be calculated from the formula:
A = Ft * S, where Ft is the force of gravity acting on the load (Ft = m * g), S is the movement of the load when falling (S = g * t ^ 2/2).
A = m * g * g * t ^ 2/2 = m * g ^ 2 * t ^ 2/2.
Let’s do the calculation:
A = 500 * 10 ^ 2 * 10 ^ 2/2 = 2500000 = 2.5 * 10 ^ 6 J = 2.5 MJ.
Answer: The force of gravity does a work of 2.5 MJ.