A load weighing 500 kg is suspended on a beam lying on supports A and B. The distance from the point

A load weighing 500 kg is suspended on a beam lying on supports A and B. The distance from the point of suspension of the load to one end of the beam is 4 times greater than to the other. With what force does the load press on each support of the beam?

Let the load suspension point C divide the beam AB in the ratio 4: 1. For definiteness, let us assume that AC = 4, CB = 1. Then AB = 5.
Consider a beam as a lever, which is acted upon by the moments of gravity F = mg and the reaction of the support A relative to the center of rotation at point B.
Answer: The beam presses on the supports with a force of 1000 N and 4000 N.