A load weighing m = 1.5 kg is lifted to a height of h = 2 m using an inclined plane and a block. The length of the inclined

| November 20, 2020 | education

A load weighing m = 1.5 kg is lifted to a height of h = 2 m using an inclined plane and a block. The length of the inclined plane is L = 8 m. The force applied to the load during this movement is F = 6 N. The efficiency of the entire lifting device is 40. What is the efficiency of the block of the block?

Determine the efficiency of the inclined plane. Work was performed W = FL, where F is the force applied to the load, L is the length of the inclined plane. In this case, useful work can be considered work that needs to be done only to lift the load without loss: Wп = mgh. The efficiency of the inclined plane is the ratio of the useful work to the expended: Kn = mgh / FS.
The overall efficiency of a mechanism consisting of several parts is equal to the product of the efficiency of each part: K = Kn * Kbl, where Kn is the efficiency of the inclined plane, Kbl is the unit efficiency.
Kbl = K / Kn = K / (mgh / FL) = 0.4 / ((1.5 kg * 10 m / s ^ 2 * 2 m) / (6 N * 8 m) = 40% / (30 / 48) = 0.4 * (8/5) = 0.64 (64%).
Answer: 64%



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