A load with a mass of m = 0.04 kg is suspended on a spring and performs free harmonic vibrations, determine the frequency

| August 5, 2021 | education

A load with a mass of m = 0.04 kg is suspended on a spring and performs free harmonic vibrations, determine the frequency v and the cyclic vibration frequency w if the spring stiffness k = 400N / m

m = 0.04 kg.

k = 400 N / m.

v -?

w -?

The frequency of oscillations v of a spring pendulum is the number of oscillations per unit of time. The frequency shows how many complete oscillations the pendulum makes in 1 second.

The frequency of a spring pendulum v is determined by the formula: v = √k / 2 * P * √m, where k is the stiffness of the spring, P is the number pi, m is the mass of the load.

v = √400 N / m / 2 * 3.14 * √0.04 kg = 15.9 Hz.

Cyclic frequency or angular w is determined by the formula: w = 2 * P * v.

w = 2 * 3.14 * 15.9 Hz = 99.85 rad / s.

Answer: v = 15.9 Hz, w = 99.85 rad / s.



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