A load with a mass of m = 100 kg is lifted at a constant speed with a light lever, the length of the short arm of which

| January 8, 2021 | education

A load with a mass of m = 100 kg is lifted at a constant speed with a light lever, the length of the short arm of which is L1 = 20 cm. Find the length of the other arm L2, if it is acted upon by a force F = 200 N directed perpendicular to the lever.

m1 = 100 kg.
g = 10 m / s2.
L1 = 20 cm = 0.2 m.
F2 = 200 N.
L2 -?
When the lever is in balance or the load is evenly lifted, the moments of forces that act from opposite sides of the lever are equal to each other: M1 = M2.
The moment of force M is called the product of the applied force F to the smallest distance from the application of force in the axis of rotation of the lever L: M = F * L.
F1 * L1 = F2 * L2.
The weight acts on the lever by the force of its weight, the value of which is determined by the formula: F1 = m1 * g.
m1 * g * L1 = F2 * L2.
L2 = m1 * g * L1 / F2.
L2 = 100 kg * 10 m / s2 * 0.2 m / 200 N = 1 m.
Answer: the length of the larger arm is L2 = 1 m.



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