A locomotive weighing 120 tons, moving at a speed of 1 m / s, is coupled with a carriage weighing 60 tons

| December 16, 2020 | education

A locomotive weighing 120 tons, moving at a speed of 1 m / s, is coupled with a carriage weighing 60 tons, moving towards the opposite at a speed of 0.8 m / s. What will be the driving speed immediately after clutching?

According to the law of conservation of momentum
p = p
But since there are two impulses, they will add up and this formula is obtained
p = p1 + p2
Now we substitute the values and convert tons to kilograms
p = 1 * 120,000 = 120,000 (kg * m / s)
p2 = 0.8 * 60,000 = 48,000 (kg * m / s)
p = 48,000 + 120,000 = 168,000 (kg * m / s)
If you thought that was all, then no. We need to find speed, not momentum.
Now we substitute the values of the total impulse and mass, since they adhered to the mass we will take the total
And we succeed
168,000 = 180,000 * V
And now we output V
V = 168,000 / 180,000 = 0.93 (m / s)
Answer: V = 0.93 (m / s)



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