A locomotive with a power of 600 W, moving evenly, travels 200 m in 20 seconds. What is its traction force?

The power of the locomotive with uniform movement is equal to:
N = A / t, where N is the power of the locomotive (N = 600 W), A is the complete mechanical work performed by the locomotive (A = F * S, where F is the traction force of the locomotive, S is the distance traveled by the locomotive (S = 200 m )), t is the time of movement (t = 20 s).
N = A / t = F * S / t.
Let us express and calculate the traction force of the locomotive:
F = N * t / S = 600 * 20/200 = 12000/200 = 60 N.
Answer: The traction force of the locomotive is 60 N.



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