A log 8 meters long 1 decimeter was sawn into two parts so that one of them is 2 times longer

A log 8 meters long 1 decimeter was sawn into two parts so that one of them is 2 times longer than the other, how many decimeter is the length of each part of the log.

Decision.
1) How many parts together make up both parts of the log if it is known from the problem statement that the log was cut into two parts so that one of them is twice as long as the other?
1 + 2 = 3 (parts).
2) How many decimetres is the length of a log 8 meters long 1 decimeter?
8 m 1 dm = 80 dm + 1 dm = 81 dm.
3) How many decimeters is the length of the smaller part of the log, obtained by sawing the log?
81: 3 = 27 (dm).
4) How many decimeters is the length of most of the log?
81 – 27 = 54 (dm).
Answer: 27 dm is the length of the smaller part of the log, obtained by sawing the log; 54 dm length of the most part of the log.



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