A machine gun is fired at a training target. Bullet weight 5 g, bullet speed 400 m / s, rate of fire 180 rounds per minute.
| March 14, 2021 | education
A machine gun is fired at a training target. Bullet weight 5 g, bullet speed 400 m / s, rate of fire 180 rounds per minute. All bullets get stuck in the target. With what average force do they act on the target?
The impulse of the force of the bullet pressure on the target is equal to the change in the momentum of the bullets:
F Δt = N m V,
where m is the mass of the bullet, m = 5 g = 0.005 kg; V – bullet velocity when leaving the bore, V = 400 m / s; N = 180 – the number of shots per time interval Δt = 1 min = 60 s.
F = N m V / Δt.
Substituting the numerical values, we find the average force of pressure on the target:
F = 180 × 0.005 × 400/60 = 6.0 N.
Answer: F = 6 N.
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