A man running at a speed of 8 m / s caught up with a cart moving at a speed of 2 m / s and jumped into it.
| February 9, 2021 | education
A man running at a speed of 8 m / s caught up with a cart moving at a speed of 2 m / s and jumped into it. As a result, the trolley speed became = 6 m / s. What is the mass of a person if the mass of the cart = 40 kg?
To find the value of the mass of a fleeing person, we apply the law of conservation of momentum: Vcht * (mh + mt) = Vh * mh + Vt * mt.
The values of the variables: Vcht – the speed of the person and the cart (Vcht = 8 m / s); mt – bogie weight (mt = 40 kg); Vh – the initial speed of a person (Vh = 2 m / s); Vt is the initial speed of the carriage (Vt = 6 m / s).
Calculation: 6 * (mh + 40) = 8 * mh + 2 * 40.
6mh + 240 = 8mh + 80.
2mh = 160.
mh = 160/2 = 80 kg.
Answer: The mass of the escaped person is 80 kg.
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