A man walks along the escalator in the direction of his movement. Determine the speed v ′ of a person

A man walks along the escalator in the direction of his movement. Determine the speed v ′ of a person relative to the escalator, if the speed of the person relative to the walls is v = 2.5 m / s, and the speed of the escalator is u = 1.2 km / h.

v1 = 2.5 meters per second – the speed of a person relative to the walls;

v2 = 1.2 kilometers per hour = 0.3 m / s – the speed of the escalator.

It is required to determine v (m / s) – the speed of a person relative to the escalator.

Since, according to the condition of the task, a person walks in the direction of movement of the escalator, then:

v1 = v2 + v, hence:

v = v1 – v2 = 2.5 – 0.3 = 2.2 meters per second.

Answer: a person moves relative to the escalator at a speed of 2.2 meters per second.



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