A man weighing 50 kg jumped from the shore into a motionless boat weighing 200 kg. The boat, together with the man

A man weighing 50 kg jumped from the shore into a motionless boat weighing 200 kg. The boat, together with the man, began to move at a speed of 1 m / s. What was the speed of the person during the jump?

According to the law of conservation of momentum
p = p1 + p2
Now, to find the speed, we substitute the values of the impulses, but in the form
p = m * V
And that’s it, substitute the values
250 = 50 * V + 0
V = 5 (m / s)
Answer: V = 5 (m / s)