A man weighing 50kg, sitting in a boat weighing 200kg on the lake, pulls the second boat weighing 200kg to him with a rope
| September 9, 2021 | education
A man weighing 50kg, sitting in a boat weighing 200kg on the lake, pulls the second boat weighing 200kg to him with a rope, the rope pulling force is 100N. The first boat will cover the distance in 10 seconds?
To find the distance that the first boat must travel, we use the formula: S = a * t ^ 2/2 = (N / (ml1 + mh)) * t2 / 2.
Values of variables: N – rope tension force (N = 100 N); ml1 is the mass of the first boat (ml1 = 200 kg); mh – human weight (mh = 50 kg); t – elapsed time (t = 10 s).
Calculation: S = (N / (ml1 + mh)) * t ^ 2/2 = (100 / (200 + 50)) * 10 ^ 2/2 = 20 m.
Answer: The first boat will cover 20 meters in 10 seconds.
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