A man weighing 60 kg is standing on a floating flat ice floe. What mass can an ice floe
| August 15, 2021 | education
A man weighing 60 kg is standing on a floating flat ice floe. What mass can an ice floe be if it is not completely submerged in water?
To find the mass of an ice floe that can hold the specified person, we will use the inequality: (ml + mh) * g <ρw * g * V.
ml * V + mh <ρw * ml / ρl.
mch <ρw * ml / ρl – ml.
mch <ml * (ρw / ρl – 1).
ml> mh / (ρw / ρl – 1).
Constants and variables: mh – human weight (mh = 60 kg); ρw is the density of water (for fresh ρw = 1000 kg / m3); ρl is the density of the ice floe (ρl = 900 kg / m3).
Calculation: ml> 60 / (1000/900 – 1).
ml> 540 kg.
Answer: The ice floe must have a mass of more than 540 kg.
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