A man weighing 60 kg, running at a speed of 5 m / s, catches up with a cart weighing 40 kg

A man weighing 60 kg, running at a speed of 5 m / s, catches up with a cart weighing 40 kg, moving at a speed of 2 m / s, and jumps on it. How fast will they continue to move?

Initial data: m1 (human weight) = 60 kg; V1 (speed of a person before jumping onto a cart) = 5 m / s; m2 (trolley weight) = 40 kg; V2 (trolley speed before a person jump) = 2 m / s.

To determine the speed of the joint movement of a person and a cart, we use the law of conservation of momentum: m1 * V1 + m2 * V2 = (m1 + m2) * V1.2.

V1.2 = (m1 * V1 + m2 * V2) / (m1 + m2) = (60 * 5 + 40 * 2) / (60 + 40) = 380/100 = 3.8 m / s.

Answer: The person with the cart will continue to move at a speed of 3.8 m / s.