A man who is heterozygous for brown eyes and polydactyly married a blue-eyed woman with a normal hand.

A man who is heterozygous for brown eyes and polydactyly married a blue-eyed woman with a normal hand. what are the probabilistic genotypes and phenotypes of the children of this marriage?

Given:
A – brown-eyed
a – blue-eyed
B – polydactyly
b – normal
To find:
F1, G
Decision:
R: AaBb♂ + aabb♀
G: AB, ab, Ab, aB ab
F1: ♂ AB Ab aAB ab
av♀ aBab Abab aBab abab
c. n. c. n. p. n.
Answer: G: AB, AB, AB, AB
F1: brown-eyed and polydactyly
brown eyes and normal
blue eyes and polydactyly
blue eyes and normal.

 



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