A marble column weighing 500 tons has a base area of 12.5 m2. Determine the column pressure on the support.

The pressure of the marble column on the base is the ratio of the force with which the mass of the marble column presses on the base to the value of the area of the base.
Hence:
P = F / S, where F is the pressure force of the marble column; F = Fт = m * g (m is the mass of the column (m = 500 t = 500,000 kg), g is the acceleration of gravity (we take g equal to 9.8 m / s ^ 2)), S is the area of the base (S = 12.5 m ^ 2).
Hence:
P = F / S = m * g / S = 500,000 * 9.8 / 12.5 = 392,000 Pa = 392 kPa.
Answer. The pressure of the marble column on the support is 392 kPa.