A marble weighing 4 g was treated with a nitric acid solution. Calculate the volume of gas produced.

In accordance with the condition of the problem, we write down the formula of the substance – CaCO3 (marble).
Let’s compose the equation for the interaction of calcium carbonate and nitric acid:
CaCO3 + 2HNO3 = Ca (NO3) 2 + CO2 + H2O – carbon dioxide is emitted;
We calculate the molar masses of substances:
M (CaCO3) = 100 g / mol;
M (CO2) = 44 g / mol.
Determine the amount of CaCO3 mol by the formula:
Y (CaCO3) = m / M = 4/100 = 0.04 mol.
According to the equation, the amount of moles of calcium carbonate and carbon monoxide (4) is equal to 1 mol, which means that Y (CO2) = 0.04 mol.
Find the volume of CO2:
V (CO2) = 0.04 * 22.4 = 0.896 l.
Answer: The volume of CO2 is 0.896 liters.