A material point moves in a straight line so that its speed at time t is equal to v (t) = t ^ 3 – e

A material point moves in a straight line so that its speed at time t is equal to v (t) = t ^ 3 – e ^ 3-t. Find its acceleration at time t = 3.

The acceleration of a material point will be equal to the first time derivative of the point’s velocity:
a (t) = V` (t) = 3t ^ 2 – 1;
Acceleration of a point at time t = 3 will be:
a (3) = 3 3 ^ 2 – 1 = 27 – 1 = 26.
Answer: The acceleration of a material point at time t = 3 is 26.



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