A material point with a mass of 1 kg moves under the action of two mutually perpendicular

A material point with a mass of 1 kg moves under the action of two mutually perpendicular forces 8N and 6N. Point acceleration equals …

Since the forces acting on a material point are mutually perpendicular (directed at an angle of 90º), we will use the Pythagorean theorem to determine the resultant force:
F² = F1² + F2², where F1 = 8 N, F2 = 6 N.
F = sqrt (F1² + F2²) = sqrt (8² + 6²) = sqrt (64 + 36) = sqrt (100) = 10 N.
According to Newton’s second law:
F = m * a, where m is the mass of a material point (m = 1 kg), and is acceleration.
Let’s calculate the body weight:
a = F / m = 10/1 = 10 m / s².
Answer: Acceleration of a point is 10 m / s².