A material point with a mass of 500 g moves with an acceleration of 2 m / s2 under the action of two forces

A material point with a mass of 500 g moves with an acceleration of 2 m / s2 under the action of two forces of equal magnitude directed at an angle of alpha = 90 degrees to each other. Determine the modulus of these forces.

According to Newton’s second law:
F = m * a, where F is the resultant of the forces acting on the point, m is the mass of the material point (m = 500 g = 0.5 kg), and is the acceleration of the material point (a = 2 m / s²).
The resultant forces acting on the point is equal to:
F = m * a = 0.5 * 2 = 1 N.
Because the forces acting on a point are equal and directed at an angle of 90º to each other, then to find them we apply the Pythagorean theorem:
F² = F1² + F2² = 2F1².
F1 = √ (F² / 2) = √ (0.5) = 0.707 N.
Answer: The modulus of forces is 0.707 N.