A metal part weighs 48.5 N in air, and when immersed in kerosene, it weighs 44.5 N.

A metal part weighs 48.5 N in air, and when immersed in kerosene, it weighs 44.5 N. What is the Archimedean force acting on a part?

Given:

P1 = 48.5 Newton – weight of a metal part measured in air;

P2 = 44.5 Newton – the weight of a metal part, measured when immersed in kerosene.

It is required to determine Farchimedes (Newton) – the Archimedean force acting on the part.

According to Newton’s first law, we have:

P2 = F gravity – Farchimedes.

Since in this case F gravity = P1, then:

P2 = P1 – Farchimedes, from here we find that:

Farchimedes = P1 – P2 = 48.5 – 44.5 = 4 Newtons.

Answer: an Archimedean force equal to 4 Newtons acts on a metal part.