A metal rod with a mass of m = 10 g and a length of L = 0.2 m is suspended on two light wires with a length of l = 10 cm in a magnetic

A metal rod with a mass of m = 10 g and a length of L = 0.2 m is suspended on two light wires with a length of l = 10 cm in a magnetic a field with induction B = 1 T which is directed vertically downward. A capacitor with a capacity of C = 100 μF, charged to a voltage of U = 100 V, is connected to the attachment points of the wires. Determine the maximum angle of deflection of the threads from the vertical position after the capacitor is discharged, if it occurs in a very short period of time. Do not take into account the resistance of the rod and wires.

Given m = 0.01 kg l = 10 cm = 0.1 m C = 100 * 10 ^ -6 F U = 100 V a-?
decision
C = Q / U
Q = C * U – capacitor charge
Δt – discharge time
I = Q / Δt – average current in the conductor
I = C * U / Δt
the ampere force acts on the conductor during Δt
F = I * B * L = C * U * B * L / Δt
according to Newton’s second law F * Δt = m * V
C * U * B * L = m * V
(C * U * B * L) ² = m² * V²
(C * U * B * L) ² / 2 * m = m * V² / 2
since m * V² / 2 = m * g * h
h = (C * U * B * L) ² / m²g
cosa = (l-h) / l = 1-h / l = 1- (C * U * B * L) ² / m²g * l
substitute the numbers yourself