A mixture of 1.48 g of potassium hydroxide and 6.6 g of ammonium sulfate was heated until the reaction was terminated.

A mixture of 1.48 g of potassium hydroxide and 6.6 g of ammonium sulfate was heated until the reaction was terminated. how many liters of ammonia were formed?

This reaction proceeds according to the following chemical reaction equation:

(NH4) 2SO4 + 2NaOH = 2NH3 + Na2SO4 + 2H2O;

Let’s calculate the chemical amount of sodium hydroxide. To do this, we divide its weight by its molar mass.

M KON = 39 + 16 + 1 = 56 grams / mol;

N KOH = 1.48 / 56 = 0.0264 mol;

Let’s calculate the chemical amount of ammonium sulfate. For this purpose, we divide its weight by its molar mass.

To do this, we divide the weight of the substance by its molar (atomic) mass.

M (NH4) 2SO4 = (14 + 4) x 2 + 32 + 16 x 4 = 132 grams / mol;

The amount of ammonium sulfate will be:

N (NH4) 2SO4 = 6.6 / 132 = 0.05 mol;

From this amount of salt, 0.05 mol of ammonia can be obtained.

Let’s find the volume of ammonia.

To this end, we multiply the amount of substance by the standard volume of 1 mole of gas (filling 22.40 liters):

V NH3 = 0.05 x 22.4 = 1.12 liters;