A mixture of 26.1 g of propanal and 8.96 L of hydrogen was passed over a platinum catalyst.

A mixture of 26.1 g of propanal and 8.96 L of hydrogen was passed over a platinum catalyst. Find the mass of the resulting alcohol.

Given:
m (C2H5CHO) = 26.1 g
V (H2) = 8.96 L

Find:
m (alcohol) -?

Solution:
1) C2H5CHO + H2 = (Pt) => C3H7OH;
2) M (C2H5CHO) = Mr (C2H5CHO) = Ar (C) * N (C) + Ar (H) * N (H) + Ar (O) * N (O) = 12 * 3 + 1 * 6 + 16 * 1 = 58 g / mol;
3) n (C2H5CHO) = m (C2H5CHO) / M (C2H5CHO) = 26.1 / 58 = 0.45 mol;
4) n (H2) = V (H2) / Vm = 8.96 / 22.4 = 0.4 mol;
5) n (C3H7OH) = n (H2) = 0.4 mol;
6) M (C3H7OH) = Mr (C3H7OH) = Ar (C) * N (C) + Ar (H) * N (H) + Ar (O) * N (O) = 12 * 3 + 1 * 8 + 16 * 1 = 60 g / mol;
7) m (C3H7OH) = n (C3H7OH) * M (C3H7OH) = 0.4 * 60 = 24 g.

Answer: The mass of C3H7OH is 24 g.