A mixture of 3 kg of gasoline and 2 kg of kerosene completely burns out. How much heat is generated in this case?

univerkov | May 3, 2021 | education

Given: mb (mass of gasoline taken) = 3 kg; mk (mass of taken kerosene) = 2 kg.

Reference values: qb (specific heat of combustion of gasoline) = 4.6 * 10 ^ 7 J / kg; qк (specific heat of combustion of kerosene) = 4.6 * 107 J / kg.

The heat that will be released during the combustion of the created mixture is calculated by the formula: Q = Qb + Qk = mb * qb + mk * qk.

Let’s perform the calculation: Q = 3 * 4.6 * 10 ^ 7 + 2 * 4.6 * 10 ^ 7 = 230 * 10 ^ 6 J (230 MJ).

Answer: When the created mixture is burned, 230 MJ of heat will be released.

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