A mixture of 6 liters of nitrogen and 15 liters of hydrogen was passed over an iron catalyst.

A mixture of 6 liters of nitrogen and 15 liters of hydrogen was passed over an iron catalyst. Determine the amount of ammonia produced.

N2 + 4H2 = 2NH4 υ (N2) = 6 l / 22.4 l / mol = 0.268 mol υ (H2) = 15 l / 22.4 l / mol / 4 = 0.1674 l / mol => H2 in deficit.
υ (NH4) = υ (H2) /2=0.0837 mol V (NH4) = 0.0837 mol * 22.4 l / mol = 1.875 l



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