A mixture of calcium carbonate and calcium oxide weighing 15.6 g was treated with hydrochloric acid, and 0.1 mol

| June 20, 2021 | education

A mixture of calcium carbonate and calcium oxide weighing 15.6 g was treated with hydrochloric acid, and 0.1 mol of gas was released. Calculate the mass of calcium carbonate and oxide.

Let’s compose the reaction equations for calcium carbonate, calcium oxide and hydrochloric acid. Let’s find the quantitative ratios of substances.

CaCO3 + 2HCl = CaCl2 + H2O + CO2.

CaO + 2HCl = CaCl2 + H2O.

According to the reaction equation, substances react 1: 1. For 1 mole of calcium carbonate, there is 1 mole of carbon dioxide.

Calcium oxide is involved in the reaction in an amount of 1 mol.

If the amount of carbon dioxide is 0.1 mol, then the amount of calcium carbonate will also be 0.1 mol.

Find the mass of calcium carbonate by the formula m = n × M.

M (CaCO3) = 100 g / mol.

m = 0.1 mol × 100 g / mol = 10 g.

Let’s find the mass of calcium oxide.

15.6 – 10 g = 5.6 g.

Answer: the mass of calcium oxide is 5.6 g; calcium carbonate 10 g.



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