A mixture of calcium hydroxide weighing 111 g and ammonium nitrate weighing 200 g was thoroughly mixed and heated.
A mixture of calcium hydroxide weighing 111 g and ammonium nitrate weighing 200 g was thoroughly mixed and heated. Calculate the amount of gas evolved.
Let’s write the reaction equation:
2NH4NO3 + Ca (OH) 2 = 2NH3 + 2H2O + Ca (NO3) 2
find the amount of substances
n (NH4NO3) = m \ M = 200 \ 80 = 2.5 mol
n (Ca (OH) 2) = m \ M = 111 \ 74 = 1.5 mol
let’s say that Ca (OH) 2 has all entered into a reaction, then NH4NO3 will react with 3 moles, which is more than given
let’s say that all NH4NO3 has entered into a reaction, then Ca (OH) 2 will react 1.25 mol, that is, less than given
It follows that there is a lack of NH4NO3, which means we are calculating on it.
Accordingly, according to the reaction equation n (NH4NO3) = n (NH3) = 2.5 mol
V (NH3) = nVm = 2.5 * 22.4 = 56 l