A mixture of gases with a volume of 20 dm3 contains 22 g No. 2 Calculate the molar concentration of gas in the mixture.

To solve the problem, you need to know the molar mass of the NO2 gas, this value is 14 + 16 * 2 = 46 g. The amount of NO2 in the mixture is 22/46 = 0.478 mol.

20 dm3 = 20 l, which means the molar volume concentration of nitrogen oxide (IV) is 0.478 / 20 = 0.024 mol / l.

The rest of the gases in 20 liters contains 20 / 22.4 – 0.478 mol = 0.415 mol, their concentration:

0.415 / 20 = 0.021 mol / L.



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