A mixture of N2 and H2 was passed over a heated catalyst. After the reaction, the volume of gases decreased by 14 liters

A mixture of N2 and H2 was passed over a heated catalyst. After the reaction, the volume of gases decreased by 14 liters. Determine the volume of the initial mixture, provided that H2 and N2 have completely reacted?

Given:
ΔV mixture = 14 l

To find:
V mixture -?

Decision:
1) Write the reaction equation:
N2 + 3H2 => 2NH3;
2) Since N2 and H2 have reacted completely, then let V (N2) = (x) n;
3) Determine the volume H2:
V (H2) = V (N2) * 3 = (x * 3) l;
4) Determine the volume of NH3:
V (NH3) = V (N2) * 2 = (x * 2) L;
5) Determine the volume of the mixture:
V mixture = V (N2) + V (H2) = x + 3x = (4x) l;
6) Determine the volume of NH3:
V (NH3) = V mixture – 14 = (4x – 14) l;
7) Make an equation and solve it:
2x = 4x – 14;
x = 7;
8) Calculate the volume of the mixture:
V mixture = 4x = 4 * 7 = 28 liters.

Answer: The volume of the mixture is 28 liters.