# A mixture of N2 and H2 was passed over a heated catalyst. After the reaction, the volume of gases decreased by 14 liters

**A mixture of N2 and H2 was passed over a heated catalyst. After the reaction, the volume of gases decreased by 14 liters. Determine the volume of the initial mixture, provided that H2 and N2 have completely reacted?**

Given:

ΔV mixture = 14 l

To find:

V mixture -?

Decision:

1) Write the reaction equation:

N2 + 3H2 => 2NH3;

2) Since N2 and H2 have reacted completely, then let V (N2) = (x) n;

3) Determine the volume H2:

V (H2) = V (N2) * 3 = (x * 3) l;

4) Determine the volume of NH3:

V (NH3) = V (N2) * 2 = (x * 2) L;

5) Determine the volume of the mixture:

V mixture = V (N2) + V (H2) = x + 3x = (4x) l;

6) Determine the volume of NH3:

V (NH3) = V mixture – 14 = (4x – 14) l;

7) Make an equation and solve it:

2x = 4x – 14;

x = 7;

8) Calculate the volume of the mixture:

V mixture = 4x = 4 * 7 = 28 liters.

Answer: The volume of the mixture is 28 liters.