A motor ship departed from pier A at a speed of 24 km / h, a barge left 9 hours earlier at a speed of 8 km / h.

| January 15, 2021 | education

A motor ship departed from pier A at a speed of 24 km / h, a barge left 9 hours earlier at a speed of 8 km / h. The barge arrived 15 hours later than the motor ship to pier B. What is the distance between pier A and pier B?

1. The distance between piers A and B is equal to: S km;
2. Speed of the ship: Vt = 24 km / h;
3. The barge speed is equal to: Vb = 8 km / h;
4. The barge left before the motor ship at: Tp = 9 hours;
5. To the pier B the barge arrived later than the motor ship at: Tn = 15 hours;
6. The motor ship was on the way time: Tt hour;
7. We compose the equation of motion of the ship and the barge:
S = Vt * Tt = Vb * (Tp + Tt + Tn);
24 * Tt = 8 * (9 + Tt + 15);
24 * Tt = 8 * 24 + 8 * Tt;
16 * Tt = 192;
Tt = 192/16 = 12 hours;
8. Distance that the ship sailed:
S = Vt * Tt = 24 * 12 = 288 km.
Answer: the distance between the marinas is 288 km.



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