A motor ship departed from pier A to pier B at a speed of 24 km / h, and 9 hours before it, a tugboat departed in the same direction at a speed of 8 km / h, which arrived at point A 15 hours later than the motor ship. Find the distance between the marinas.
1. We take as x the length of the path of the ship and the tug between the quays.
2. Considering that the ship was on the way less than the tug by 9 + 15 = 24 hours, we make the equation:
x / 8 – x / 24 = 24;
2x / 24 = 24;
2x = 576;
x = 288 kilometers.
Answer: the length of the route of the motor ship and the tugboat by the quays is 288 kilometers.
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