A motorcycle moving with an acceleration of 4 m / s, Stopped in 10s, What is the distance to the stop?

These tasks: a (acceleration, which the given motorcyclist had) = 4 m / s2; t (duration of movement to stop) = 10 s; slow motion.

1) Determine the initial speed of a given motorcyclist: V = 0 = V0 – a * t and V0 = a * t = 4 * 10 = 40 m / s.

2) Calculate the distance to the stop: S = (V ^ 2 – V0 ^ 2) / (2 * (-a)) = V0 ^ 2 / 2a = 40 ^ 2 / (2 * 4) = 200 m.

Check: S = V0 * t – a * t ^ 2/2 = 40 * 10 – 4 * 10 ^ 2/2 = 400 – 200 = 200 m (correct).

Answer: The distance is 200 meters.