A motorcyclist moving at a speed of 72 km / h began to brake and stopped after 4 seconds the mass of the motorcyclist

A motorcyclist moving at a speed of 72 km / h began to brake and stopped after 4 seconds the mass of the motorcyclist and the motorcycle is 250 kg, the braking force modulus is?

v0 = 72 km / h = 20 m / s – the initial speed of the motorcyclist;

t = 4 seconds – the time from the start of braking to the complete stop of the motorcyclist;

m = 250 kilograms is the mass of a motorcycle and a motorcyclist.

It is required to determine F (Newton) – the motorcyclist’s braking modulus.

Let’s find the acceleration with which the motorcyclist braked:

a = v0 / t = 20/4 = 5 m / s2.

Then, according to Newton’s second law, the modulus of the braking force will be equal to:

F = m * a = 250 * 5 = 1250 Newton.

Answer: the modulus of the braking force acting on the motorcyclist is 1250 Newtons.