A motorcyclist, moving from a state of rest, covers 1 km of path with an acceleration of 0.8 m / s2.

| August 9, 2021 | education

A motorcyclist, moving from a state of rest, covers 1 km of path with an acceleration of 0.8 m / s2. Find the motorcyclist’s acceleration time and speed at the end of this path.

V0 = 0 m / s.

S = 1 km = 1000 m.

a = 0.8 m / s2.

t -?

V -?

With uniformly accelerated motion of the body, the traversed path S is determined by the formula: S = V0 * t + a * t ^ 2/2, where V0 is the initial velocity of the body, t is the time of motion, and a is the acceleration during motion. Since the motorcyclist starts his movement from a state of rest V0 = 0 m / s, the formula will take the form: S = a * t ^ 2/2.

t = √ (2 * S / a).

t = √ (2 * 1000 m / 0.8 m / s2) = 50 s.

We express the final speed of the motorcyclist V from the formula for acceleration: a = (V – V0) / t.

V = V0 + a * t.

V = a * t.

V = 0.8 m / s2 * 50 s = 40 m / s.

Answer: t = 50 s, V = 40 m / s.



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