# A nickel-plated conductor with a length of 10 m carries a current of 0.5 A.

August 17, 2021 | education

| **A nickel-plated conductor with a length of 10 m carries a current of 0.5 A. Determine the cross-sectional area of the conductor if a voltage of 20 V is applied to its ends.**

Given: l (length of nickel conductor used) = 10 m; I (current in the conductor) = 0.5 A; U (applied voltage) = 20 V.

Constants: ρ (specific resistance of nickelin (20 ºС)) = 0.4 Ohm * mm2 / m.

To determine the cross-sectional area of the nickelin conductor used, use the equation: U / I = ρ * l / S, whence S = ρ * l * I / U.

Calculation: S = ρ * l * I / U = 0.4 * 10 * 0.5 / 20 = 0.1 mm2.

Answer: The cross-sectional area of the nickeline conductor used is 0.1 mm2.

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