A non-Kylin wire with a cross section of 0.1 mm ^ 2 is stretched between the tripods. What is the voltage

A non-Kylin wire with a cross section of 0.1 mm ^ 2 is stretched between the tripods. What is the voltage at the ends of this wire, if its length is 0.5 m, and the ammeter shows 0.75 A. The specific resistance of nickel is 42 * 10 ^ (- 8) ohm * m

Given:

s = 0.1 mm2 – cross-sectional area of nickel wire;

l = 0.5 meters – the length of the nickel wire;

r = 42 * 10-8 Ohm * m = 0.42 Ohm * mm2 / m is the specific resistance of nickel;

I = 0.75 Amperes – current in the electrical circuit.

It is required to determine U (Volt) – the voltage at the ends of the nickel wire.

Find the total resistance of the wire:

R = r * l / s = 0.42 * 0.5 / 0.1 = 0.21 / 0.1 = 2.1 Ohm.

Then the voltage at the ends of the wire can be found from the following formula (Ohm’s law):

U = I * R = 0.75 * 2.1 = 1.6 Volts (the result has been rounded to one decimal place).

Answer: the voltage is 1.6 volts.