A package was dropped from the helicopter, which was descending uniformly at a speed of 6 m / s. After 8 seconds

A package was dropped from the helicopter, which was descending uniformly at a speed of 6 m / s. After 8 seconds, he fell to the surface of the earth. Set the height from which you dropped.

Initial data: V0 (speed of uniform descent of the helicopter, initial speed of the packet) = 6 m / s; t (packet fall duration) = 8 s.

Reference values: g (acceleration of gravity, acceleration of a packet) ≈ 10 m / s2.

The height from which the packet was dropped is determined by the formula: H = V0 * t + 0.5 * g * t ^ 2.

Calculation: H = 6 * 8 + 0.5 * 10 * 8 ^ 2 = 368 m.

Answer: The package was dropped from a helicopter at an altitude of 368 meters.