# A part was lowered into a cylindrical vessel containing 6 dm3 of water. At the same time, the level of the liquid

October 1, 2021 | education

| **A part was lowered into a cylindrical vessel containing 6 dm3 of water. At the same time, the level of the liquid in the vessel increased 1.5 times. What is the volume of the part?**

Let the plane of the base of the cylinder be Sbn dm2, and the height of the liquid in the vessel is h cm.

Then the volume of liquid in the vessel will be equal to:

V1 = Sbn * h cm3 = 6 dm3.

After immersion in the vessel of the part, the liquid level became equal to 1.5 * h dm.

Since the liquid level has risen 1.5 times, the volume will also increase 1.5 times.

V2 = S main * 1.5 * h = 6 * 1.5 = 9 dm3.

Then the difference in volumes is the volume of the immersed part.

V = V2 – V1 = 9 – 6 = 3 dm3.

Answer: The volume of the part is 3 dm3.

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